We focused on questions in the calculator section that she was having trouble with.

The first had a bag of marbles and was about finding probabilities. The basic idea is to find the number of specific option(s) you want and divide by the total number of options. There are variations on that.

For another problem, the vertex of a parabola was needed. You can use -b/2a to get the x-coordinate. That can also be derived using calculus by taking the derivative of ax^2 + bx + c and setting it equal to zero since the slope at the vertex is zero.

Sometimes using different forms of an equation, including what is originally listed, can be more useful for certain applications than a derived form.

Getting a common denominator is important for some problems.

The SAT often has answers that you would arrive at by making common mistakes.

Mean, median, and mode can show up. Most common would be mean (average).

sin^2x + cos^2x = 1, that showed up in practice.

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